Answer
(3, 0) or (-5, -4)
Work Step by Step
2y = x - 3 can be written as x = 2y + 3. Plug this into $y^{2} = x^{2} - 9$
$y^{2} = (2y + 3)^{2} - 9$
$y^{2} = 4y^{2} + 12y + 9 - 9$
$0 = 3y^{2} + 12y$
Divide both sides by 3
$0 = y^{2} + 4y$
Factor
$0 = y(y + 4)$
y = 0 or y + 4 = 0
y = 0 or -4
Plug y-values into x = 2y + 3
x = 2(0) + 3 = 3
x = 2(-4) + 3 = -5
(3, 0) or (-5, -4)
