Answer
$(-3,5),(2,0)$
Work Step by Step
$x+y=2$
$y=x^2-4$
$x+x^2-4=2$
$x^2+x-6=0$
$(x+3)(x-2)=0$
$x=-3,2$
$-3+y=2$
$y=5$
$2+y=2$
$y=0$
$(-3,5),(2,0)$
College Algebra (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-32178-228-3
ISBN 13:
978-0-32178-228-1
Chapter 5 - Systems of Equations and Inequalities - Exercise Set 5.4 - Page 559: 1
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