Answer
$(-6,7),(-2,-1)$
Work Step by Step
$2x+y=-5$
$y=x^2+6x+7$
$2x+x^2+6x+7=-5$
$x^2+8x+12=0$
$(x+6)(x+2)=0$
$x=-6,-2$
$2(-6)+y=-5$
$-12+y=-5$
$y=7$
$2(-2)+y=-5$
$-4+y=-5$
$y=-1$
$(-6,7),(-2,-1)$
College Algebra (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-32178-228-3
ISBN 13:
978-0-32178-228-1
Chapter 5 - Systems of Equations and Inequalities - Exercise Set 5.4 - Page 559: 4
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