Answer
$(0,1),(1,2)$
Work Step by Step
$x-y=-1$
$y=x^2+1$
$x-x^2-1=-1$
$-x^2+x+0=0$
$x^2-x+0=0$
$(x+0)(x-1)=0$
$x=0,1$
$0-y=-1$
$y=1$
$1-y=-1$
$y=2$
$(0,1),(1,2)$
College Algebra (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-32178-228-3
ISBN 13:
978-0-32178-228-1
Chapter 5 - Systems of Equations and Inequalities - Exercise Set 5.4 - Page 559: 2
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