Answer
(3, -5) or (-1,3)
Work Step by Step
2x + y = 1 can be written as y = 1 - 2x. Plug this into $x^{2} + y = 4$
$x^{2} + 1 - 2x = 4$
$x^{2} - 2x - 3 = 0$
(x - 3)(x + 1) = 0
x - 3 = 0 or x + 1 = 0
x = 3 or -1
Plug x-values into y = 1 - 2x
y = 1 - 2(3) = -5
y = 1 - 2(-1) = 3
(3, -5) or (-1,3)
