Answer
$(1,1),(2,0)$
Work Step by Step
$x+y=2$
$y=x^2-4x+4$
$x+x^2-4x+4=2$
$x^2-3x+2=0$
$(x-2)(x-1)=0$
$x=1,2$
$1+y=2$
$y=1$
$2+y=2$
$y=0$
$(1,1),(2,0)$
College Algebra (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-32178-228-3
ISBN 13:
978-0-32178-228-1
Chapter 5 - Systems of Equations and Inequalities - Exercise Set 5.4 - Page 559: 3
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