Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 4 - Section 4.5 - Exponential and Logarithmic Functions - 4.5 Exercises - Page 368: 7

Answer

$x=-3$

Work Step by Step

$7^{2x-3}=7^{6+5x}$ Simply use the one-to-one property to solve this equation. Make the exponents on both sides of the equation equal.: $2x-3=6+5x$ Take the $5x$ to the left side of the equation and the $-3$ to the right side: $2x-5x=6+3$ Simplify both sides: $-3x=9$ Solve for $x$: $x=-\dfrac{9}{3}$ $x=-3$
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