Chapter 4 - Section 4.5 - Exponential and Logarithmic Functions - 4.5 Exercises - Page 368: 61

$x=-7$

$4-\log(3-x)=3$ Take the $4$ to substract the right side of the equation: $-\log(3-x)=-1$ Multiply both sides by $-1$: $\log(3-x)=1$ Write this equation in exponential form: $3-x=10^{1}$ Solve for $x$: $-x=10-3$ $-x=7$ $x=-7$