Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 4 - Section 4.5 - Exponential and Logarithmic Functions - 4.5 Exercises - Page 368: 26

Answer

$x=-\dfrac{100\log2}{\log5}\approx-43.067656$

Work Step by Step

$5^{-x/100}=2$ Apply $\log$ to both side of the equation: $\log5^{-x/100}=\log2$ The exponent $-x/100$ can be taken down to multiply in front of its respective $\log$: $-\dfrac{x}{100}\log5=\log2$ Solve for $x$: $-x=\dfrac{100\log2}{\log5}$ $x=-\dfrac{100\log2}{\log5}\approx-43.067656$
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