Answer
$x=5$
Work Step by Step
$\log_{2}3+\log_{2}x=\log_{2}5+\log_{2}(x-2)$
Combine the logarithms on the left and right side of the equation as a products:
$\log_{2}3x=\log_{2}(5x-10)$
Since $\log$ is one to one, the equation becomes:
$3x=5x-10$
Solve for $x$:
$3x-5x=-10$
$-2x=-10$
$x=5$
