Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 4 - Section 4.5 - Exponential and Logarithmic Functions - 4.5 Exercises - Page 368: 4

Answer

$x=\pm3$

Work Step by Step

$e^{x^{2}}=e^{9}$ Simply use the one-to-one property to solve this equation. $x^{2}=9$ Take the square root of both terms: $\sqrt{x^{2}}=\sqrt{9}$ $x=\pm3$
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