Answer
a. $\log \frac {3}{x-2} = \log x$
b. $\frac{3}{x-2} = x$
c. x = 3
Work Step by Step
a-c. are all fill in the blank questions
Given $\log 3 + \log (x-2) = \log x$
a. Combine the left hand side to get the equation of $\log \frac {3}{x-2} = \log x$
b. The next step is to raise both sides by the power of 10, so the equation will now be $\frac{3}{x-2} = x$
c. Solve for x. $3 = x(x-2)$
$x^2 - 2x - 3 = 0$
$(x-3)(x+1) = 0$
$x = 3, -1$
However, x has a domain of (0, ∞), so x can not be -1
Thus x = 3
