Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 4 - Section 4.5 - Exponential and Logarithmic Functions - 4.5 Exercises - Page 368: 6

Answer

$x=1$

Work Step by Step

$10^{2x-3}=\dfrac{1}{10}$ Rewrite this equation as $10^{2x-3}=10^{-1}$: $10^{2x-3}=10^{-1}$ Use the one-to-one property to solve this equation: $2x-3=-1$ Solve for $x$: $2x=-1+3$ $2x=2$ $x=\dfrac{2}{2}$ $x=1$
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