Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 4 - Section 4.5 - Exponential and Logarithmic Functions - 4.5 Exercises - Page 368: 19

Answer

$t=\dfrac{\log\dfrac{10}{3}}{\log(1.025)^{12}}\approx4.063202$

Work Step by Step

$300(1.025)^{12t}=1000$ Take the $300$ to divide the right side of the equation: $1.025^{12t}=\dfrac{1000}{300}$ Simplify the right side: $1.025^{12t}=\dfrac{10}{3}$ Apply $\log$ to both sides of the equation: $\log1.025^{12t}=\log\dfrac{10}{3}$ Applying the power of a power rule, the left side of the equation can be written like this: $\log(1.025^{12})^{t}=\log\dfrac{10}{3}$ Take down the exponent $t$ to multiply in front of the $\log$: $t\log(1.025)^{12}=\log\dfrac{10}{3}$ Solve for $t$: $t=\dfrac{\log\dfrac{10}{3}}{\log(1.025)^{12}}\approx4.063202$
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