Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 4 - Section 4.5 - Exponential and Logarithmic Functions - 4.5 Exercises - Page 368: 24

Answer

$x=\dfrac{\log34}{\log8}\approx1.695821$

Work Step by Step

$2^{3x}=34$ Apply $\log$ to both sides of the equation: $\log2^{3x}=\log34$ Using the power of a power rule, we can rewrite the expression on the left side of the equation like this: $\log(2^{3})^{x}=\log34$ $\log8^{x}=\log34$ The exponent $x$ can be taken down to multiply in front of its respective $\log$: $x\log8=\log34$ Solve for $x$: $x=\dfrac{\log34}{\log8}\approx1.695821$
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