Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 2: Limits and Continuity - Practice Exercises - Page 101: 44

Answer

$0$

Work Step by Step

When $\theta\to\infty$, the function $cos\theta$ will oscillate in a range of $[-1,1]$. We have $cos\theta-1$ oscillates in a range of $[-2,0]$. Thus: $\lim_{\theta\to\infty}\frac{cos\theta-1}{\theta}=0$
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