Answer
$-\infty $
Work Step by Step
Given $$\lim _{t \rightarrow 3^{+}} \ln (t-3)$$
Let $ x=t-3$. Then
\begin{align*} \lim _{t \rightarrow 3^{+}} \ln (t-3)&=\lim _{x \rightarrow 0^{+}} \ln x\\
&=-\infty
\end{align*}
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 2: Limits and Continuity - Practice Exercises - Page 101: 25
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