Answer
$$0$$
Work Step by Step
\begin{align*}
\lim _{x \rightarrow \infty} \frac{1}{x^{2}-7 x+1}&=\lim _{x \rightarrow \infty} \frac{\frac{1}{x^{2}}}{1-\frac{7}{x}+\frac{1}{x^{2}}}\\
&=\frac{0}{1-0+0}\\
&=0
\end{align*}
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 2: Limits and Continuity - Practice Exercises - Page 101: 40
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