Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 2: Limits and Continuity - Practice Exercises - Page 101: 21

Answer

$$1$$

Work Step by Step

\begin{aligned} \lim _{x \rightarrow \pi} \sin \left(\frac{x}{2}+\sin x\right)&=\sin \left(\frac{\pi}{2}+\sin \pi\right)\\ &=\sin \left(\frac{\pi}{2}\right)\\ &=1 \end{aligned}
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