Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 2: Limits and Continuity - Practice Exercises - Page 101: 41

Answer

$-\infty $

Work Step by Step

\begin{align*} \lim _{x \rightarrow-\infty} \frac{x^{2}-7 x}{x+1}&=\lim _{x \rightarrow-\infty} \frac{x-7}{1+\frac{1}{x}}\\ &=-\infty \end{align*}
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