Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 2: Limits and Continuity - Practice Exercises - Page 101: 37

Answer

$$\frac{2}{5}$$

Work Step by Step

\begin{align*} \lim _{x \rightarrow \infty} \frac{2 x+3}{5 x+7}&=\lim _{x \rightarrow \infty} \frac{2+\frac{3}{x}}{5+\frac{7}{x}}\\ &=\frac{2+0}{5+0}\\ &=\frac{2}{5} \end{align*}
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