Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 2: Limits and Continuity - Practice Exercises - Page 101: 22

Answer

$$1$$

Work Step by Step

\begin{aligned} \lim _{x \rightarrow \pi} \cos ^{2}(x-\tan x)&=\cos ^{2}(\pi-\tan \pi)\\ &=\cos ^{2}(\pi)\\ &=(-1)^{2}\\ &=1 \end{aligned}
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