Answer
$0$
Work Step by Step
The limit of the numerator $\lim_{x\to1}(3x^2+1)=4$. Thus, for the entire limit to be $\infty$, the denominator needs to be zero. Therefore, we have $\lim_{x\to1}g(x)=0$
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.