Answer
$0$
Work Step by Step
The limit of the numerator $\lim_{x\to1}(3x^2+1)=4$. Thus, for the entire limit to be $\infty$, the denominator needs to be zero. Therefore, we have $\lim_{x\to1}g(x)=0$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 2: Limits and Continuity - Practice Exercises - Page 101: 27
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