Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 2: Limits and Continuity - Practice Exercises - Page 101: 15



Work Step by Step

\begin{align*} \lim _{x \rightarrow 0} \frac{\frac{1}{2+x}-\frac{1}{2}}{x}&=\lim _{x \rightarrow 0} \frac{2-(2+x)}{2 x(2+x)}\\ &=\lim _{x \rightarrow 0} \frac{-1}{4+2 x}\\ &=-\frac{1}{4} \end{align*}
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