Answer
$$\frac{2}{5}$$
Work Step by Step
\begin{align*}
\lim _{x \rightarrow-\infty} \frac{2 x^{2}+3}{5 x^{2}+7}&=\lim _{x \rightarrow-\infty} \frac{2+\frac{3}{x^{2}}}{5+\frac{7}{x^{2}}}\\
&=\frac{2+0}{5+0}\\
&=\frac{2}{5}
\end{align*}
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