Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 2: Limits and Continuity - Practice Exercises - Page 101: 11

Answer

$$\frac{1}{2}$$

Work Step by Step

\begin{align*} \lim _{x \rightarrow 1} \frac{1-\sqrt{x}}{1-x}&=\lim _{x \rightarrow 1} \frac{1-\sqrt{x}}{(1-\sqrt{x})(1+\sqrt{x})}\\ &=\lim _{x \rightarrow 1} \frac{1}{1+\sqrt{x}}\\ &=\frac{1}{2} \end{align*}
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