Answer
$$0$$
Work Step by Step
\begin{align*}
\lim _{x \rightarrow-\infty} \frac{x^{2}-4 x+8}{3 x^{3}}&=\lim _{x \rightarrow-\infty}\left(\frac{1}{3 x}-\frac{4}{3 x^{2}}+\frac{8}{3 x^{3}}\right)\\
&=0-0+0\\
&=0
\end{align*}
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 2: Limits and Continuity - Practice Exercises - Page 101: 39
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
