Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 2: Limits and Continuity - Practice Exercises - Page 101: 20

Answer

$\infty $

Work Step by Step

\begin{aligned} \lim _{x \rightarrow \pi^{-}} \csc x&=\lim _{x \rightarrow \pi^{-}} \frac{1}{\sin x}, \ (\sin x\to 0,\ \text{as} x \rightarrow \pi^{-})\\ &=\infty \end{aligned}
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