Answer
$\displaystyle \frac{1}{4}(2x+4)\cdot|2x+4|+C$
Work Step by Step
$\displaystyle \int|2x+4|dx=$
Shortcut formula:
$\displaystyle \qquad\int|ax+b|dx =\displaystyle \frac{1}{2a}(ax+b)|ax+b|+C$
Apply with $ \left[\begin{array}{l}
a=2\\
b=4
\end{array}\right]$
$=\displaystyle \frac{1}{2(2)}(2x+4)|2x+4|+C$
= $\displaystyle \frac{1}{4}(2x+4)\cdot|2x+4|+C$
