Answer
$x=-\displaystyle \frac{3}{4}$
Work Step by Step
$y=f(x)=2x^{2}+3x-1$
$f^{\prime}(x)=2(2x)+3-0=4x+3$
$f^{\prime}(x)=0$ for ... (solve for x)
$4x+3=0$
$4x=-3$
$x=-\displaystyle \frac{3}{4}$
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