Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 11 - Section 11.1 - Derivatives of Powers, Sums, and Constant Multiples - Exercises - Page 795: 22

Answer

$g^{\prime}(x)=-2x^{-2}-8x^{-3}$

Work Step by Step

SUMMARY: The Power Rule$:\ \ \ [x^{n}]^{\prime}=nx^{n-1 } $ Sum Rule: $\ \ \ \ \ \ [f\pm g]^{\prime}(x)=f^{\prime}(x)\pm g^{\prime}(x) $ Constant Multiple Rule:$\ \ \ [cf]^{\prime}(x)=cf^{\prime}(x) $ Constant times x:$\ \ \ \displaystyle \frac{d}{dx}(cx)=c $ Constant:$\displaystyle \ \ \ \ \ \frac{d}{dx}(c)=0 $ -------------------------------- $g^{\prime}(x)=[2x^{-1}+4x^{-2}]^{\prime}=... $Sum Rule, $=[2x^{-1}]^{\prime}+[4x^{-2}]^{\prime}=$... individually: $[2x^{-1}]^{\prime}=$...Constant Multiple Rule... $=2[x^{-1}]^{\prime}$=...power rule...$=2(-1\cdot x^{-2})=-2x^{-2}$ $[4x^{-2}]^{\prime}=$...Constant Multiple Rule... $=4[x^{-2}]^{\prime}$=...power rule...$=4(-2x^{-3})=-8x^{-3}$ So $g^{\prime}(x)=-2x^{-2}-8x^{-3}$
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