Answer
$\displaystyle \frac{1}{3}$
Work Step by Step
$f^{\prime}(x)=[\displaystyle \frac{1}{3}x-1]^{\prime}=\frac{1}{3}-0=\frac{1}{3}$
the slope of the tangent at x=$-3$
$=f^{\prime}(-3)=\displaystyle \frac{1}{3}$
Finite Math and Applied Calculus (6th Edition)
by Waner, Stefan; Costenoble, Steven
Published by
Brooks Cole
ISBN 10:
1133607705
ISBN 13:
978-1-13360-770-0
Chapter 11 - Section 11.1 - Derivatives of Powers, Sums, and Constant Multiples - Exercises - Page 795: 56
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