Answer
$-\displaystyle \frac{3}{16}$
Work Step by Step
$s^{\prime}(t)=[t^{-3}]^{\prime}=-3t^{-4}$
the slope of the tangent at $t=-2$
$=s^{\prime}(-2)=-3(-2)^{-4}=\displaystyle \frac{-3}{16}$
Finite Math and Applied Calculus (6th Edition)
by Waner, Stefan; Costenoble, Steven
Published by
Brooks Cole
ISBN 10:
1133607705
ISBN 13:
978-1-13360-770-0
Chapter 11 - Section 11.1 - Derivatives of Powers, Sums, and Constant Multiples - Exercises - Page 795: 58
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