Answer
$y=3x+2 \\$
Work Step by Step
1. The tangent line at x=a passes through the point (a, f(a))$\\$
(we must first find f(a)$\\$
2. It has slope m$=f^{\prime}(a)\\$
3. Its equation (point slope): $y-f(a)=f^{\prime}(a)(x-a)\\$
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1. $x=-1, \ \ \ f(-1)$=$(-1)^{3}=-1.\\$
The point on the graph is $(-1,-1).\\$
2. Slope. $\\$
$f^{\prime}(x)=$ (power rule)$ = 3x^{2}\\$
$m=f^{\prime}(-1)=3(-1)^{2}=3\\$
3. Equation. P($ -1, -1 $), $m=3 \\$
$y-(-1)=3(x-(-1)) \\$
$y+1=3x+3 \\$
$y=3x+2 \\$
image enclosed: graph