Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.1 - The Greatest Common Factor and Factoring by Grouping - Exercise Set - Page 427: 91



Work Step by Step

$2 $ is a factor of all three terms $x^{2}$ also, and so is $(x+1).$ $GCF=2x^{2}(x+1)$ $ \begin{array}{ccc} 4x^{5}(x+1) & -6x^{3}(x+1) & -8x^{2}(x+1)=\\ =2x^{2}(x+1)\cdot 2x^{3} & +2x^{2}(x+1)\cdot(-3x) & +2x^{2}(x+1)\cdot(-4) \end{array}$ = $2x^{2}(x+1)(2x^{3}-3x-4)$
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