## Introductory Algebra for College Students (7th Edition)

$2x^{2}(x+1)(2x^{3}-3x-4)$
$2$ is a factor of all three terms $x^{2}$ also, and so is $(x+1).$ $GCF=2x^{2}(x+1)$ $\begin{array}{ccc} 4x^{5}(x+1) & -6x^{3}(x+1) & -8x^{2}(x+1)=\\ =2x^{2}(x+1)\cdot 2x^{3} & +2x^{2}(x+1)\cdot(-3x) & +2x^{2}(x+1)\cdot(-4) \end{array}$ = $2x^{2}(x+1)(2x^{3}-3x-4)$