Answer
$(x^{3}-5)(1+2y)$
Work Step by Step
There are no common factors (for all four terms).
Reorder and factor by grouping:
$...=x^{3}+2x^{3}y-5-10y$
$=x^{3}\cdot 1+x^{3}\cdot 2y+(-5)\cdot 1+(-5)\cdot 2y$
... use distribution, group by group
$=x^{3}(1+2y)+(-5)(1+2y)$
... use distribution, common factor: $(1+2y)$
= $(x^{3}-5)(1+2y)$
