Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.1 - The Greatest Common Factor and Factoring by Grouping - Exercise Set - Page 427: 90



Work Step by Step

There are no common factors (for all four terms). Reorder and factor by grouping: $...=x^{3}+2x^{3}y-5-10y$ $=x^{3}\cdot 1+x^{3}\cdot 2y+(-5)\cdot 1+(-5)\cdot 2y$ ... use distribution, group by group $=x^{3}(1+2y)+(-5)(1+2y)$ ... use distribution, common factor: $(1+2y)$ = $(x^{3}-5)(1+2y)$
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