Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.1 - The Greatest Common Factor and Factoring by Grouping - Exercise Set: 38

Answer

$y^2(26y^3-13y+39)$

Work Step by Step

Factoring the $GCF= y^2 ,$ the given expression, $ 26y^5-13y^3+39y^2 ,$ is equivalent to \begin{array}{l}\require{cancel} y^2 \left( \dfrac{26y^5}{y^2}-\dfrac{13y^3}{y^2}+\dfrac{39y^2}{y^2} \right) \\\\= y^2(26y^3-13y+39) .\end{array}
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