Answer
$5(4y^2+3)$
Work Step by Step
Factoring the $GCF=
5
,$ the given expression, $
20y^2+15
,$ is equivalent to
\begin{array}{l}\require{cancel}
5
\left(
\dfrac{20y^2}{5}+\dfrac{15}{5}
\right)
\\\\=
5(4y^2+3)
.\end{array}
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