Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.1 - The Greatest Common Factor and Factoring by Grouping - Exercise Set: 24

Answer

$5(4y^2+3)$

Work Step by Step

Factoring the $GCF= 5 ,$ the given expression, $ 20y^2+15 ,$ is equivalent to \begin{array}{l}\require{cancel} 5 \left( \dfrac{20y^2}{5}+\dfrac{15}{5} \right) \\\\= 5(4y^2+3) .\end{array}
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