Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.1 - The Greatest Common Factor and Factoring by Grouping - Exercise Set - Page 427: 40

Answer

$2x(3-2x+x^2)$

Work Step by Step

Factoring the $GCF= 2x ,$ the given expression, $ 6x-4x^2+2x^3 ,$ is equivalent to \begin{array}{l}\require{cancel} 2x \left( \dfrac{6x}{2x}-\dfrac{4x^2}{2x}+\dfrac{2x^3}{2x} \right) \\\\= 2x(3-2x+x^2) .\end{array}
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