Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.1 - The Greatest Common Factor and Factoring by Grouping - Exercise Set: 34

Answer

$3(5y^2-y+3)$

Work Step by Step

Factoring the $GCF= 3 ,$ the given expression, $ 15y^2-3y+9 ,$ is equivalent to \begin{array}{l}\require{cancel} 3 \left( \dfrac{15y^2}{3}-\dfrac{3y}{3}+\dfrac{9}{3} \right) \\\\= 3(5y^2-y+3) .\end{array}
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