## Introductory Algebra for College Students (7th Edition)

Published by Pearson

# Chapter 6 - Section 6.1 - The Greatest Common Factor and Factoring by Grouping - Exercise Set - Page 427: 85

#### Answer

$(x-a)(x-b)$

#### Work Step by Step

Using factoring by grouping, the given expression, $x^2-ax-bx+ab ,$ is equivalent to \begin{array}{l}\require{cancel} (x^2-ax)-(bx-ab) \\\\= x(x-a)-b(x-a) \\\\= (x-a)(x-b) .\end{array}

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