Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.1 - The Greatest Common Factor and Factoring by Grouping - Exercise Set - Page 427: 85



Work Step by Step

Using factoring by grouping, the given expression, $ x^2-ax-bx+ab ,$ is equivalent to \begin{array}{l}\require{cancel} (x^2-ax)-(bx-ab) \\\\= x(x-a)-b(x-a) \\\\= (x-a)(x-b) .\end{array}
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