Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.1 - The Greatest Common Factor and Factoring by Grouping - Exercise Set: 77

Answer

$(y+5)(x+9)$

Work Step by Step

Using factoring by grouping, the given expression, $ xy+5x+9y+45 ,$ is equivalent to \begin{array}{l}\require{cancel} (xy+5x)+(9y+45) \\\\= x(y+5)+9(y+5) \\\\= (y+5)(x+9) .\end{array}
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