# Chapter 6 - Section 6.1 - The Greatest Common Factor and Factoring by Grouping - Exercise Set - Page 427: 84

$(4x-1)(x^2-3)$

#### Work Step by Step

Using factoring by grouping, the given expression, $4x^3-x^2-12x+3 ,$ is equivalent to \begin{array}{l}\require{cancel} (4x^3-x^2)-(12x-3) \\\\= x^2(4x-1)-3(4x-1) \\\\= (4x-1)(x^2-3) .\end{array}

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