Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.1 - The Greatest Common Factor and Factoring by Grouping - Exercise Set - Page 427: 78

Answer

$(y+6)(x+2)$

Work Step by Step

Using factoring by grouping, the given expression, $ xy+6x+2y+12 ,$ is equivalent to \begin{array}{l}\require{cancel} (xy+6x)+(2y+12) \\\\= x(y+6)+2(y+6) \\\\= (y+6)(x+2) .\end{array}
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