Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.1 - The Greatest Common Factor and Factoring by Grouping - Exercise Set - Page 427: 46



Work Step by Step

Factoring the $GCF= 9xy ,$ the given expression, $ 27x^2y^3-18xy^2+45x^2y ,$ is equivalent to \begin{array}{l}\require{cancel} 9xy \left( \dfrac{27x^2y^3}{9xy}-\dfrac{18xy^2}{9xy}+\dfrac{45x^2y}{9xy} \right) \\\\= 9xy(3xy^2-2y+5x) .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.