## Introductory Algebra for College Students (7th Edition)

Published by Pearson

# Chapter 6 - Section 6.1 - The Greatest Common Factor and Factoring by Grouping - Exercise Set - Page 427: 83

#### Answer

$(3x-2)(x^2-2)$

#### Work Step by Step

Using factoring by grouping, the given expression, $3x^3-2x^2-6x+4 ,$ is equivalent to \begin{array}{l}\require{cancel} (3x^3-2x^2)-(6x-4) \\\\= x^2(3x-2)-2(3x-2) \\\\= (3x-2)(x^2-2) .\end{array}

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