Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.1 - The Greatest Common Factor and Factoring by Grouping - Exercise Set - Page 427: 27

Answer

$y(13y-25)$

Work Step by Step

Factoring the $GCF= y ,$ the given expression, $ 13y^2-25y ,$ is equivalent to \begin{array}{l}\require{cancel} y \left( \dfrac{13y^2}{y}-\dfrac{25y}{y} \right) \\\\= y(13y-25) .\end{array}
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