Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.1 - The Greatest Common Factor and Factoring by Grouping - Exercise Set - Page 428: 92



Work Step by Step

$2 $ is a factor of all three terms $x^{2}$ also, and so is $(x+2).$ $GCF=2x^{2}(x+2)$ $ \begin{array}{ccc} 8x^{5}(x+2) & -10x^{3}(x+2) & -2x^{2}(x+2)=\\ =2x^{2}(x+2)\cdot 4x^{3} & +2x^{2}(x+2)\cdot(-5x) & +2x^{2}(x+2)\cdot(-4) \end{array}$ = $2x^{2}(x+2)(4x^{3}-5x-4)$
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