## Introductory Algebra for College Students (7th Edition)

$4x^{2}(9-\pi)$
The area of a square = $($side length$)^{2}$ The area of a circle = $\pi\cdot($radius$)^{2}$ Shaded area = (area of square) - (area of circle) $=(6x)^{2}-\pi\cdot(2x)^{2}$ $=36x^{2}-\pi\cdot 4x^{2}$ GCF of the terms is $4x^{2}$. Use the distributive property to factor: $=4x^{2}\cdot 9-4x^{2}\cdot\pi$ $=4x^{2}(9-\pi)$