Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.1 - The Greatest Common Factor and Factoring by Grouping - Exercise Set - Page 428: 95



Work Step by Step

The area of a square = $($side length$)^{2}$ The area of a circle = $\pi\cdot($radius$)^{2}$ Shaded area = (area of square) - (area of circle) $=(6x)^{2}-\pi\cdot(2x)^{2}$ $=36x^{2}-\pi\cdot 4x^{2}$ GCF of the terms is $4x^{2}$. Use the distributive property to factor: $=4x^{2}\cdot 9-4x^{2}\cdot\pi$ $=4x^{2}(9-\pi)$
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