Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.1 - The Greatest Common Factor and Factoring by Grouping - Exercise Set - Page 428: 113


False. The statement could become true if we write: $a^{2}+b^{2}$ can not be factored.

Work Step by Step

First step: adding 0 = ab-ab does not change the result (OK). Second step: ERROR in factoring of the second group. It should read: $=a(a+b)-b(a-b)$ So the next step does not follow, since there is no common binomial to extract. (no factorization possible)
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